What is the relationship between keV and kVp? - Physics ...

kVp is the maximum voltage in an X-Ray tube. When electrons travel through the voltage V, they will gain the kinetic energy of E=eV. Since e ... PhysicsStackExchangeisaquestionandanswersiteforactiveresearchers,academicsandstudentsofphysics.Itonlytakesaminutetosignup. Signuptojointhiscommunity Anybodycanaskaquestion Anybodycananswer Thebestanswersarevotedupandrisetothetop Home Public Questions Tags Users Unanswered Teams StackOverflowforTeams –Collaborateandshareknowledgewithaprivategroup. CreateafreeTeam WhatisTeams? Teams CreatefreeTeam Teams Q&Aforwork Connectandshareknowledgewithinasinglelocationthatisstructuredandeasytosearch. Learnmore WhatistherelationshipbetweenkeVandkVp? AskQuestion Asked 7years,9monthsago Active 6years,4monthsago Viewed 32ktimes 0 $\begingroup$ OnX-raytopicswegetusedtotalkabout"energy",butwhatiskeV?andwhatistherelationshipbetweenkeVandkVp? energypotentialsi-unitsx-rays Share Cite Improvethisquestion Follow editedAug20'15at23:50 Qmechanic♦ 159k3030goldbadges392392silverbadges18781878bronzebadges askedMar18'14at22:21 user42807user42807 111goldbadge11silverbadge11bronzebadge $\endgroup$ 3 2 $\begingroup$ keViskiloelectronvolts,anelectronvoltistheenergyanelectronacquiresbymovingthroughapotentialdifferenceof1V.I'mnotsurewhatkVpmeans,canyouclarify? $\endgroup$ – Elvex Mar18'14at22:28 1 $\begingroup$ @user42807couldyoupleasetrytoclearupyourquestionabit?Asofrightnow,itishardtounderstandwhatexactlyyou'reasking. $\endgroup$ – Danu Mar18'14at22:45 1 $\begingroup$ WikipediaquicklygiveswhatkVpisinanX-Raycontext,sothisisnotthatunclear. $\endgroup$ – MartinUeding Mar18'14at22:51 Addacomment  |  2Answers 2 Active Oldest Votes 2 $\begingroup$ kVpisthemaximumvoltageinanX-Raytube.Whenelectronstravelthroughthevoltage$V$,theywillgainthekineticenergyof$E=eV$.Since$e$isverysmallinSIunits,anddoesnotreallytellyoumuch,theenergyofanelectrontravelingthough$1\,\mathrmV$isusedasaenergyunit,namely$\mathrm{eV}$with$1\mathrm{eV}=e\cdot1\,\mathrmV$. TheenergyandfrequencyofyourX-Rayphotonwillberelatedwith$E=hf=\hbar\omega$.Where$f$isthefrequencyand$\omega$istheangularfrequency.$2\pif=\omega$. Share Cite Improvethisanswer Follow editedMar18'14at22:52 answeredMar18'14at22:41 MartinUedingMartinUeding 8,12344goldbadges3434silverbadges5656bronzebadges $\endgroup$ 1 $\begingroup$ +1especiallyfortakingthetimetoanswertheOP's"unclear"question.IwasbrowsingthroughyourMSccourseworkonyourblogtoseewhat'staughtthesedays:lookslikeyouhadfun. $\endgroup$ – SeleneRoutley Aug21'15at1:26 Addacomment  |  1 $\begingroup$ Intermsofradiography/radiology,kVpisthetubevoltage/tubepotentialbetweenthecathodeandtheanode,setbytheoperator.TheuniteV(orkeVasusedintherangeofgeneralradiography,MeVasusedbyRadiationTherapy)describestheenergyoftheparticles-inthiscase,theelectronsinthex-raytube,andthex-rayphotonscomingofftheanodeandtowardsthepatient. Soastheelectronsinthetubeareacceleratedacrossthetubevoltage,theywillgainthesamekineticenergyasthetubepotential-so,ifforexamplethekVpwas100kV,theelectronenergywillbe100keVastheyreachtheanode. However,theconversionfromelectronenergytophoton(x-ray)energyintheanodeisofvaryingefficiency.Sothex-raybeamemittedwillhaveanenergyspectrum(measuredinkeVinradiographyforconvenience,althoughitwouldnormallybemeasuredinHzelsewhereinphysics).ThebottomoftherangeiszerokeV,thetopoftherangecannotbehigherthantheenergysuppliedbythetubepotential,inthisexample100kVp-sothemostenergeticx-rayswillbe(almost)100keV,buttherewon'tbeverymanyofthem. Foraregulartungstenanode,wherethemajorityoftheradiationisgeneratedbybremsstralunginteractions,andgiventypicalexitwindowfiltration,theaveragekeVwillberoughly1/3rdofthekVp.Thiswillchangedependingontheexaminationthough.Formammographywheremostoftheradiationisgeneratedthroughcharacteristicradiation,andspecificfiltersareused,theaveragex-raykeVcouldbequitedifferentfrom1/3rdofthekVp. Hencetheterm"kVp"standsfor"kilovoltspeak",becauseitdefinesthetopkeVvaluethex-rayscanhave. Share Cite Improvethisanswer Follow editedAug21'15at0:01 answeredAug20'15at23:41 ClintClint 1122bronzebadges $\endgroup$ Addacomment  |  YourAnswer ThanksforcontributingananswertoPhysicsStackExchange!Pleasebesuretoanswerthequestion.Providedetailsandshareyourresearch!Butavoid…Askingforhelp,clarification,orrespondingtootheranswers.Makingstatementsbasedonopinion;backthemupwithreferencesorpersonalexperience.UseMathJaxtoformatequations.MathJaxreference.Tolearnmore,seeourtipsonwritinggreatanswers. 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